(2x^2-5y)(2x^2+5y)=

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Solution for (2x^2-5y)(2x^2+5y)= equation:


Simplifying
(2x2 + -5y)(2x2 + 5y) = 0

Multiply (2x2 + -5y) * (2x2 + 5y)
(2x2 * (2x2 + 5y) + -5y * (2x2 + 5y)) = 0
((2x2 * 2x2 + 5y * 2x2) + -5y * (2x2 + 5y)) = 0

Reorder the terms:
((10x2y + 4x4) + -5y * (2x2 + 5y)) = 0
((10x2y + 4x4) + -5y * (2x2 + 5y)) = 0
(10x2y + 4x4 + (2x2 * -5y + 5y * -5y)) = 0
(10x2y + 4x4 + (-10x2y + -25y2)) = 0

Reorder the terms:
(10x2y + -10x2y + 4x4 + -25y2) = 0

Combine like terms: 10x2y + -10x2y = 0
(0 + 4x4 + -25y2) = 0
(4x4 + -25y2) = 0

Solving
4x4 + -25y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '25y2' to each side of the equation.
4x4 + -25y2 + 25y2 = 0 + 25y2

Combine like terms: -25y2 + 25y2 = 0
4x4 + 0 = 0 + 25y2
4x4 = 0 + 25y2
Remove the zero:
4x4 = 25y2

Divide each side by '4'.
x4 = 6.25y2

Simplifying
x4 = 6.25y2

Combine like terms: 6.25y2 + -6.25y2 = 0.00
x4 + -6.25y2 = 0.00

Factor a difference between two squares.
(x2 + 2.5y)(x2 + -2.5y) = 0.00

Subproblem 1

Set the factor '(x2 + 2.5y)' equal to zero and attempt to solve: Simplifying x2 + 2.5y = 0 Solving x2 + 2.5y = 0 Move all terms containing x to the left, all other terms to the right. Add '-2.5y' to each side of the equation. x2 + 2.5y + -2.5y = 0 + -2.5y Combine like terms: 2.5y + -2.5y = 0.0 x2 + 0.0 = 0 + -2.5y x2 = 0 + -2.5y Remove the zero: x2 = -2.5y Simplifying x2 = -2.5y The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(x2 + -2.5y)' equal to zero and attempt to solve: Simplifying x2 + -2.5y = 0 Solving x2 + -2.5y = 0 Move all terms containing x to the left, all other terms to the right. Add '2.5y' to each side of the equation. x2 + -2.5y + 2.5y = 0 + 2.5y Combine like terms: -2.5y + 2.5y = 0.0 x2 + 0.0 = 0 + 2.5y x2 = 0 + 2.5y Remove the zero: x2 = 2.5y Simplifying x2 = 2.5y The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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